bence imkansız çünkü; t=tek ç=çift ise t+t=ç yapar(her zaman) öyleyse yedi tane tek rakam toplamı (t+t)+(t+t)+(t+t)+t şeklinde yazılır.3.(t+t)+t olur. 3.(t+t)=çift olur ve hiçbir zaman ç+t=çift sayı(40)yapmaz
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t=tek
ç=çift ise
t+t=ç yapar(her zaman) öyleyse
yedi tane tek rakam toplamı
(t+t)+(t+t)+(t+t)+t şeklinde yazılır.3.(t+t)+t olur.
3.(t+t)=çift olur ve hiçbir zaman
ç+t=çift sayı(40)yapmaz
bunların toplamıda tek olcagından
cevap tek olmalıdır
o yüzdenddir ki
40 olanaqsız
1+3!+5+7+9+11+1=40
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